21p^2+16pq-5q^2=0

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Solution for 21p^2+16pq-5q^2=0 equation:


Simplifying
21p2 + 16pq + -5q2 = 0

Reorder the terms:
16pq + 21p2 + -5q2 = 0

Solving
16pq + 21p2 + -5q2 = 0

Solving for variable 'p'.

Factor a trinomial.
(21p + -5q)(p + q) = 0

Subproblem 1

Set the factor '(21p + -5q)' equal to zero and attempt to solve: Simplifying 21p + -5q = 0 Solving 21p + -5q = 0 Move all terms containing p to the left, all other terms to the right. Add '5q' to each side of the equation. 21p + -5q + 5q = 0 + 5q Combine like terms: -5q + 5q = 0 21p + 0 = 0 + 5q 21p = 0 + 5q Remove the zero: 21p = 5q Divide each side by '21'. p = 0.2380952381q Simplifying p = 0.2380952381q

Subproblem 2

Set the factor '(p + q)' equal to zero and attempt to solve: Simplifying p + q = 0 Solving p + q = 0 Move all terms containing p to the left, all other terms to the right. Add '-1q' to each side of the equation. p + q + -1q = 0 + -1q Combine like terms: q + -1q = 0 p + 0 = 0 + -1q p = 0 + -1q Remove the zero: p = -1q Simplifying p = -1q

Solution

p = {0.2380952381q, -1q}

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